(2x-5)(5x+8)=10x^2-9x-40

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Solution for (2x-5)(5x+8)=10x^2-9x-40 equation: 



(2x-5)(5x+8)=10x^2-9x-40

We move all terms to the left:

(2x-5)(5x+8)-(10x^2-9x-40)=0

We get rid of parentheses

-10x^2+(2x-5)(5x+8)+9x+40=0

We multiply parentheses ..

-10x^2+(+10x^2+16x-25x-40)+9x+40=0

We get rid of parentheses

-10x^2+10x^2+16x-25x+9x-40+40=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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